0=10u^2-13u+4

Solution for 0=10u^2-13u+4 equation:

0=10u^2-13u+4

We move all terms to the left:

0-(10u^2-13u+4)=0

We add all the numbers together, and all the variables

-(10u^2-13u+4)=0

We get rid of parentheses

-10u^2+13u-4=0

a = -10; b = 13; c = -4;
Δ = b2-4ac
Δ = 132-4·(-10)·(-4)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-3}{2*-10}=\frac{-16}{-20}
=4/5
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+3}{2*-10}=\frac{-10}{-20}
=1/2
$